Comments on: Calculate the number of days between two dates

By: cody

cody — Mon, 14 Sep 2009 08:56:57 +0000

check out this one:
http://kenno.wordpress.com/2009/07/04/php-number-of-days-between-two-dates/

greetz

By: Craig

Craig — Mon, 14 Sep 2009 08:17:29 +0000

OK I guessed that it wanted day, month, year as separate values, so I did this:

$tdd=date(“j”);
$tdm=date(“n”);
$tdy=date(“Y”);

…

$std=date(“j”,strtotime($row['life_time']));
$stm=date(“n”,strtotime($row['life_time']));
$sty=date(“Y”,strtotime($row['life_time']));

echo days_between($std,$stm,$sty,$tdd,$tdm,$tdy);

NOW it works :) I don’t know if there’s a shorter way though lol

By: Craig

Craig — Mon, 14 Sep 2009 06:40:21 +0000

When I echo:

echo days_between(21,8,2009,1,9,2009);

or another manually entered date(s) this function works fine. However, I need to use variables and then it gives a Warning for ‘Missing Arguement’. I tried:

echo days_between($lt,$today);

where:

$today=date(“j,n,Y”);

and $lt comes from a database result:

$lt=date(“j,n,Y”,strtotime($row['life_time']));

If I echo $lt I get the correct database result displayed and likewise $today displays the correct day’s date.

Any ideas what I’m doing wrong?

Thanks!
Craig.